Question

find all the three angles of the ABC angle A=(x+35)°,B=(2x-5)°,C=(4x-15)°​

Answer 1

In ∆ABC

A= (x+35)°,B= (2x-5)° ,C= (4x-15)°

The sum of all angles of triangle is 180°

A+B+C = 180°

x+35+2x-5+4x-15 = 180

7x+15 = 180

7x= 180-15

7x =165

x = 165 /7

1) A = 165/7 + 35 = 59 ° (approx.) 2)B =2 × 165 /7- 5 = 42 ° (approx.) 3)C = 4 × 165 /7- 15 = 79° (approx.) I hope it will help you

Answer 2

Answer:

by using the angle formula:

the sum of interior opposite angle is equal to the exterior angle.

i.e

interior angles are (x+35 )° and (2x-5 )°

exterior angel is ( 4x-15)°

so 4x-15 = x+35 + 2x-5

4x-15 = 3x+30

4x-3x = 30 + 15

x = 45°

answer x = 45°