Find all the three digit numbers whose digit in the hundreds place is three
times the digit in the units place and the digit in the tens place is 1.
Answers
Answered by
3
Answer:
Let the digit in ten's place be x.
Then, the digit in the hundred's place =
3
x
and digit in the unit's place = 4×
3
x
=
3
4x
∴ The original number = 100×
3
x
+10×x+
3
4x
=
3
100x
+10x+
3
4x
=
3
100x+30x+4x
=
3
134x
In the new number,
Digit in the ten's place =
3
4x
Digit in the unit's place =x
Digit in the hundred's place =
3
x
100×
3
x
+10×
3
4x
+x=
3
100x+40x+3x
=
3
143x
Given,
3
143x
−
3
134x
=18
⇒
3
9x
=18
⇒x=6
∴ Original number =
3
134
×6=268
∴25% of 268=
100
25
×268=
4
268
=67
Answered by
1
311,612,913 I think this would be the correct answer
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