Question

Find all the trigonometric ratios for the following triangle
please help me​

Answer 1

Answer:

Here,

P = Perpendicular, B = Base, H = Hypotenuse

Sin 45° = 1 / ✓2 = P/H

1/✓2= x/✓2x

x=1

cosec 45°= 1/ sin 45° = 1 / (1/✓2) = ✓2 = H/P

✓2 = √2x/x

x= 1

cos 45° = 1 / ✓2 = B/H

1/√2 = x / √2x

x= 1

sec 45° = 1/ cos 45° = 1 / (1/√2) = ✓2 = H/B

√2 = √2x / x

x=1

tan 45° =1 = P/B

1 = x / x

x = 1

cot 45° =1/ tan 45° = 1 = B/P

1 = x / x

x = 1