find all the zero of the polynomial p(x)=2x²+7x³-19x²-14x+30 if two of its zeros are √2and√-2
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Polynomial f(x) = 2x⁴+7x³-19x²-14x+30
√2 and –√2. are zeroes of the polynomial.
Then (x+√2) and (x-√2) are factors of the polynomial and they divide the polynomial.
So (x+√2)*(x-√2) = x²+2
2x⁴+7x³-19x²-14x+30 / (x² - 2) = 2x² + 7x -15
Now let's factorize 2x² + 7x -15
2x² + 7x -15 = 0
2x² +10x -3x -15 = 0
2x (x+5) -3(x+5) = 0
(2x-3) (x+5) = 0
So the other roots are x = 3/2 and x = -5
Step-by-step explanation:
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