Find all the zeroa of the polinomial x^4-3x^3-8x^2+12x+16 if two of its zeroes are 4 and -1
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Answer:
let the zeros be (x-4) & (x+1)
Step-by-step explanation: multiply both the zeros,
⇒ (x-4)(x+1) = x^2+x-4x-4
⇒ x^2-3x-4 -(1)
now divide eq. (1) by the given eq.,
=> x^2-3x-4
3x^3-8x^2+12x+16
=> x^2-4 = 0
=> x^2 = 4
=> x = √4
=> x = 2
∴ required zeros are 2 & 0
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