Math, asked by siddharthbalajii2004, 11 months ago

Find all the zeroa of the polinomial x^4-3x^3-8x^2+12x+16 if two of its zeroes are 4 and -1​

Answers

Answered by harshsm
1

Answer:

let the zeros be (x-4) & (x+1)

Step-by-step explanation: multiply both the zeros,

                        ⇒ (x-4)(x+1) = x^2+x-4x-4

                        ⇒ x^2-3x-4                               -(1)

now divide eq. (1) by the given eq.,

                        =>        x^2-3x-4          

                             3x^3-8x^2+12x+16  

                        =>  x^2-4 = 0

                        =>  x^2 = 4

                        =>  x = √4

                        =>  x = 2

                ∴ required zeros are 2 & 0      

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