Question

Find all the zeroerof 2x4-3x3-3x2+6x-2 Its two zeros areroot2and-root2

Answer 1

Answer:

x=1/2 and x=1

Step-by-step explanation:

zeros of the polynomial are root2 and -root2

(x+root2)(-xroot2)

=x^2-2

when we devide 2x4-3x3-3x2+6x-2 by x2-2

=2x2-3x+1

factor karne par

(2x-1)(x-1)=0

x=1/2 and x= 1