Question

find all the zeroes of 2x4-3x3-3x2+6x-2, given two of its zeroes are √2 and -√2.

Answer 1

Answer: zeroes are :- -√2,+√2, 0.5 & 1

Step-by-step explanation:

2x^4 - 3x^3 - 3x^2 + 6x - 2 = 0

On expanding

(x - √2)(x + √2)(x - 1/2)(x - 1) = 0

Hence roots are,

x = -√2, √2, 1/2 & 1

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