find all the zeroes of 2x⁴-3x³-3x²-6x-2, if it is given two of its zeroes are 1 and ½
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Answer:
-1 and +1
Step-by-step explanation:
let,
1=b
1/2=a
and c and d be the all four zeros of the polynomial.
we know that,
a+ b+ c+ d=-B/A
that is -(-3)/2
so, 1+1/2+c+d=3/2
so, c+d=0,c=-d
abcd= E/A
that's -2/2=-1
1 ×1/2× c × d =-1
so, c×d=-2
-d(d) =-2
d^2=2
d=√2
hence c=-√2
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