Find all the zeroes of, 2x4 - 3x3 - 3x2 + 6x - 2 if you know that two of its zeroes are √2 and -√2 .
Answers
Answered by
37
Answer:
if√2and -√2 are two zeroes, then two factors are x-√2 and x+√2
product of these two factors=x^2-2
(2x^4-3x^3-3x^2+6x-2)÷(x^2-2)=
2x^2-3x+1
factorize this you will get
(x-1)(2x-1)
x-1=0 and 2x-1=0
x=1 and x=1/2
This polynomial has degree four, so there will be four zeroes and they are
√2, -√2, 1 and 1/2
Answered by
0
the zeroes are √2,-√2, 1, 1/2
Similar questions