Question

find all the zeroes of 2x⁴-3x³-3x²+6x-2,if you know that two of its zeroes are √2 and -√2.​

Answer 1

Answer:

$\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star$

Step-by-step explanation:

$Given, \: Two \: Zeroes: √2 , -√2$

$This \: can \: also \: be \: written \: as:$

$(x-√2)(x+√2)$

$[ (a+b)(a-b) = a²-b²]$

$= x²-2$

$Now, \: dividing \: polynomial \\ \: by \: this \: we \: get :$

$[Solution \: is \: there \: in \: image]$

$2x²-3x+1$

$=> 2x²-2x-x+1$

$=> 2x(x-1)-1(x-1)$

$=> (2x-1)(x-1)$

$=> 2x-1 = 0 \: \: \: \: \: \: \: \: \: x-1=0$

$= > 2x=1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = > x=1$

$= x= \frac{1}{2}$

$Therefore, all \: the \: Zeroes \: of \: \\ polynomial \: are √2, \: -√2, \: \frac{1}{2} \: ,1.$

$please \: like \: my \: answer \\ \&\\ mark \: me \: brainliest \: please \: :)))$

$\star\large\mathcal{\underline{\underline{PLEASE \: }}}\large\mathcal\red{\underline{\underline{F}}}\large\mathcal\green{\underline{\underline{OLL}}}\large\mathcal\pink{\underline{\underline{OW \: }}}\large\mathcal\blue{\underline{\underline{ME}}}\star$

$\star \: i \: hope \: you \: will \: understand \: me\star$