find all the zeroes of f(x)=x^2+4x
Answers
Answered by
1
Answer:
0,-4
Step-by-step explanation:
x^2+4x=0
x^2=-4x
x^2/x = -4
x= -4
sum of the roots in a quadratic equation is -b/a
-4 + another root = -4 /1
-4 + another root = -4
another root = 0
therefore the roots are 0,-4.
Answered by
1
f(x) = x^2 + 4x
Rewrite
y = x^2 + 4x
Replace y to 0
x^2 + 4x = 0
Factor out x
x (x + 4) = 0
x = 0, x + 4 = 0
x = 0, x = -4
The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y with 0 and solve for x.
x = 0, x = -4
Rewrite
y = x^2 + 4x
Replace y to 0
x^2 + 4x = 0
Factor out x
x (x + 4) = 0
x = 0, x + 4 = 0
x = 0, x = -4
The roots (zeros) are the x values where the graph intersects the x-axis. To find the roots (zeros), replace y with 0 and solve for x.
x = 0, x = -4
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