Question

Find all the zeroes of p(x) = x3 -9x2 -12x + 20 if (x+2) is a factor of p(x).

Answer 1

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Given that

x + 2 is a factor of p(x)

x + 2 = 0

x = -2

PUTTING THE VALUE OF X OF P(X)

p(x) = x³ - 9x² - 12x + 20

p(-2) = (-2)³ - 9 × (-2)² - 12 × (-2) + 20

p(-2) = -8 - 9 × 4 + 24 + 20

p(-2) = -8 - 36 + 24 + 20

p(-2) = -44 + 44

p(-2) = 0

Hence,

( x + 2) is a factor of p(x).

Step-by-step explanation:

Answer 2

Answer:

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