Question

Find all the zeroes of the cubic polynomial x^3-x^2-10x-8

Answer 1

Answer:

just follow a simple and straight method that is

first take the product of the first and last no.(s)

here we can see that the first no. is 1 and last is 8 multiply them we have to take the LCM

lcm=1,2,2,2,8

right!

try these no.(s)

as negative and positive too

so let the no. be (x+1),(x-1),(x+2),(x-2),(x+8), and (x-8)

the first,

p(-1)=(-1)^3-(-1)^2-10(-1)-8

-1-1+10-8

=10-10

=0

it means (x+1) is the zero of the polynomial f(x)

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hope it hepls

#answerwithquality

#bal

Answer 2

all three zeroes are -1, -2, 4