Question

find all the zeroes of the polynomial 2x^3-x^2-5x-2 if two of its zeroes are -1 and 2 (with proper explanation please, brainliest will be chosen.)​

Answer 1

Answer:

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Answer 2

Let

$p(x) = 2x^3-x^2-5x-2$

Two of the zeroes of p(x) is given to us as -1 and 2

That means (x+1) and (x-2) are factors of p(x)

That again means (x+1)(x-2) is a factor of p(x)

$(x+1)(x-2) = x^2-x-2$

is a factor of p(x)

(2x³ - x² - 5x -2) ÷ (x² - x - 2)

Carry out the above step by long division method.

You will get quotient 2x+1 and remainder 0

So (2x+1) is a factor of p(x)

x = -1/2 is the other zero.