Find all the zeroes of the polynomial 2x^3 + x^2- 6x – 3. if two of its zeroes are -V3 and V3.
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Answer:
Step-by-step explanation:
2x³+x²-6x-3
a=2 b=1 c=-6 d=-3
A=-√3 B=√3 G=?
(Note: A->alpha, B->beta, G->gama)
A + B + G = -b/a (rule)
-√3+ √3 +G = -1/2
0 + G = -1/2
G = -1/2 -0
.'. G = -1/2
Done!!
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