Find all the zeroes of the
polynomial
3 2
p(x)= 2x +x-6x-3 if two of its
zeroes are
-V3 and √3.
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f( x) = 2x³+ x² - 6x-3
Since the zeroes of f( x) are root 3 and -root 3 , the factors are x- root 3 and x+ root 3 respectively.
Therefore, ( x- root 3)× (x+
root 3)
= (x) ²- ( root 3) ²
= x²- 3
x²- 3 ) 2x³+ x²- 6x-3 ( 2x+1
2x³ - 6x
(–)_____(+)_______
x² -3
x² -3
___(-)____(+)_____
0 0
Therefore 2x+1=0
or, x= - 1/2
So, the zeroes of f(x) are
-root 3 , root 3 and -1/2.
Hope it helps you.
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