Question

Find all the zeroes of the polynomial 4 + 3 − 342 − 4 + 120 , if two of

its zeroes are (2) and (-2).​

Answer 1

Answer:

Since two zeroes are 2 and –2.

x = 2 or x = –2

=> ( x – 2 ) ( x + 2 ) = 0

=> x² – 4

So, x² – 4 is a factor of given polynomial.

Refer to the attachment for division.

Now, x² + x – 30 = 0

x² + 6x – 5x – 30 = 0

x ( x + 6 ) – 5 ( x + 6 ) = 0

( x – 5 ) ( x + 6 ) = 0

( x – 5 ) = 0 or ( x + 6 ) = 0

x = 5 of x = –6

Thus, the zeroes of x⁴ + x³ – 34x² – 4x + 120 are 2, –2, 5 and –6.

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Hope my ans.'s satisfactory. (^-^)

Explanation:

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