find all the zeroes of the polynomial f(x)=2x⁴-3x³-3x²+6x-2, if two of its zeros are √2 and -√2
Answers
Answer:
Given √2 and -√2 are two zeroes.
So (x - √2) and (x - -√2) are the factors.
i. e., (x - √2) & (x + √2) are the factors.
So, (x - √2)(x + √2)is also a factor.
i. e., x²- (√2)² = x² - 2 is a factor.
_2x² _- _3x_+_1_____
x² - 2 |2x⁴ - 3x³ - 3x² + 6x - 2
|2x⁴ - 4x²
|__________________
| - 3x³ + x² + 6x - 2
| - 3x³ + 6x
|__________________
x² - 2
x² - 2
__________________
0
2x² - 3x + 1
a + b = -3
a × b = 2
-1 + -2 = -3
-1 × -2 = 2
2x² - 3x + 1 = 0
2x² - 2x - 1x + 1 = 0
2x(x - 1) - 1(x - 1) = 0
(2x - 1)(x- 1) = 0
2x - 1 = 0 OR x - 1 = 0
2x = 1 x = 1
x = 1/2
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Step-by-step explanation:
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