find all the zeroes of the polynomial f(x) = x^4+x^3-23x-3x+60, if it is given that two of its zeroes are 5 and 4
Answers
Answered by
4
Answer:
(x - root3)*(x + root3) is one factor
By using identity
(x^2 - 3) is one factor
x^4 + x^3 - 23x^2 - 3x + 60 / x^2 - 3
= x^2 + x - 20
The zeroes of x^2 + x - 20 are -5 and 4
All the zeroes of the given polynomial are
root3, -root3, -5, 4
Answered by
3
Answer:
Hii
Let f(x) = x4 + x3 – 23x2 – 3x + 60. Since √3 and –√3 are the zeroes of f(x), it follows that each one of (x – √3) and (x + √3) is a factor of f( x).
Similar questions