Question

Find all the zeroes of the polynomial x^3+3x^2-x-3

Answer 1

Answer:

x³+3x²-2x-6= (x²-2)(x+3)

Step-by-step explanation:

If two zeroes are √2 and -√2

so, the factor will be

(x-√2)(x+√2) =0

⇒x²-2=0

now, dividing the expression with this,

x²-2)x³+3x²-2x-6( x+3

      x³       -2x

    -          +

         +3x²-6

         +3x²-6

         -      +

           0     0

so,x³+3x²-2x-6= (x²-2)(x+3)