Find all the zeroes of the polynomial x3+3x2-4x-12 , if one of its zeroes is -3.
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Answer:
x³+3x²-4x-12=0
x²(x+3) -4(x+3)= 0
(x²-4) (x+3)=0
(x²-4) =0, x+3=0
x²=4, x=-3
x=±2, x=-3
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