Question

find all the zeroes of the polynomial x3+3x2-4x-12 if one of its zeroes is -3

Answer 1

Solution is in the attached image..

Answer 2

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Here is your answer
${x}^{3} + 3 {x}^{2} - 4x - 12 = 0 \\ {x}^{2} (x + 3) - 4(x + 3) = 0 \\ (x + 3)( {x}^{2} - 4) = 0 \\ x + 3 = 0 \\ x = - 3 \\ or \\ {x}^{2} - 4 = 0 \\ {x}^{2} = 4 \\ x = \sqrt{4} \\ x = 2 \: \: and \: - 2$
Therefore the roots of the equation are
-3 , 2. and -2

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