find all the zeroes of the polynomial x³+3x²-5x-15, if two of its zeroes are √5 and -√5
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Step-by-step explanation:
Let the three zeroes are alpha, beta & gama .
We know that
for this Cubic polynomial x³ + 3x² - 5x - 15
alpha + beta + gama = -b/a
√5 + (-√5) + gama = -3/1 = -3
√5 - √5 + gama = -3
gama = -3
Third zero is -3 .
So , all the zeroes are √5 , -√5 & -3 .
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