Find all the zeroes of the polynomial x4
– 5x3 + 2x2+10x-8, if two of its zeroes are 4 and 1.
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Answered by
0
−
2
,
2
are two zeros it means (x+
2
)(x−
2
) are its factor
or say (x
2
−2) is the factor hence we can write
x
2
−2)
x
4
−5x
3
+2x
2
+10x−8
(x
2
−5x+4
±x
4
∓2x
2
−5x
3
+4x
2
+10x∓5x
3
∓10x
4x
2
−8±4x
2
∓8
∴x
4
−5x
3
+2x
2
+10x−8=(x
2
−2)(x
2
−5x+4)
=(x
2
−2)(x−4)(x−1)
Hence other two zeros are 1,4
∴ Sum =5
Answered by
2
Zero is 14 sum 5
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