Question

Find all the zeroes of the polynomial x4 +x3-34x2-4x+120,if two of its are 2 and -2

Answer 1

Hii friend,

(X-2) (X+2) = X²-(2)² = X²-4

P(X) = X⁴+X³-34X²-4X+120

And,

G(X) = (X²-4)

On dividing P(X) by G(X) we get,

Remainder = 0

Quotient = X²+X-30

Factories the Quotient then we will get the other zeros of the polynomial.

=> X²+X-30

=> X²+6X-5X-30.

=> X(X+6) -5(X+6)

=> (X+6)(X-5)

=> (X+6) = 0 OR (X-5) = 0

=>X = -6 OR X = 5

Hence,

-6 , 5 , -2 and 2 are the four zeros of the polynomial X⁴+X³-34X²-4X+120.


HOPE IT WILL HELP YOU..... :-)

Answer 2

Answer:

hope it helps you!!!!!!!!!!!!!