Question

find all the zeroes of x^3+3x^2-2x-6, if it's two zeroes are -√2&√2

Answer 1

Given:

• Two zeroes are -√2&√2

To Find:

• all the zeroes of x^3+3x^2-2x-6

Solution:

Let the factors be x+√2 and x-√2

$(x + \sqrt{2} )(x - \sqrt{2} ) = {x}^{2} - 2$

Note: Please refer to attachment for division

Therefore the remaining factor is x+3

$g(x) = x + 3 \\ 0 = x + 3 \\ \boxed{x = ( - 3)}$

Therefore, √2,-√2 and (-3) are zeroes of polynomial x^3+3x^2-2x-6

#helpingismypleasure

@ItsRuchikahere