Math, asked by Rndy2004, 4 hours ago

find all the zeroes of x^3-4x^2+x+6 , given that x=-1 is a zero of the polynomial

Answers

Answered by errrhack593

1

Answer:

36

Step-by-step explanation:

2346+546++44876-456789/45=780/4*5

Answered by ThunderGod1

1

Answer:

x3 - 4x2 = -5

Step-by-step explanation:

x3 - 4x2 + x + 6 = x = 1
x3 - 4x2 + x - x = 1 - 6
x3 - 4x2 = - 5

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