Question

Find all the zeroes of x^3-x^2-4x+4 if one of its zero is -2

Answer 1

x^3 - x^2 -4 * x + 4

= x^2(x - 1) - 4(x - 1)

= (x - 1) * (x^2 - 4)

= (x - 1) * (x - 2) * (x + 2) Ans...

Answer 2

Let p(x) be x^3-x^2-4x+4

If the zero is -2

Then x = -2

x +2=0

Then divide p(x) by x+2

There the quotient from dividing p(x) is x^2-3x+2 {q(x)}

Therefore find the zero of q(x)

x^2-x-2x+2=0

x(x-1)-2(x-1)=0

(x-1) (x-2)=0

x-1=0 ;x-2=0

x=1 ;x=2

Therefore all the zeroes of p(x) are 1,2,&-2