find all the zeroes of x3+11x2+23x-35 if two of its zeroes are 1 and -5
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Answer:
-7 ,1, -5
Step-by-step explanation:
Let the zeros be a,b,c
We know that : a+b+c = -1 × coefficient of x² / coefficient of x³
∴ 1+(-5)+c = -11
∴ c = -7
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