Question

Find all the zeroes of x4 - 3x² - 26x²+54x-27,
given that two of its zeroes are 3root3 and - 3root3.​

Answer 1

Answer:

Step-by-step explanation:

x=3√3

⇒x-3√3=0

and,  x=-3√3

⇒x+3√3=0

g(x)=(x-3√3)(x+3√3)

     =x²-27

Now,

x²-27 ÷ x4 -2x3-26x2+54x-27

=x²-2x+1

now solving(x²-2x+1)

q(x)=x²-x-x+1

      =x(x-1)-1(x-1)

      =(x-1)(x-1)

Hence, other roots of the given p(x) are:   (x-1)

Hope it helped you!!...