find all the zeros for 2x³ - 3x² - 8x + 12
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Answer:
Zeroes of the polynomial are 2 , -2 , 3/2
Step-by-step explanation:
2x³-3x²-8x+12
= 2x²-4x²+x²-2x-6x+12
= 2x²(x-2)+x(x-2)-6(x-2)
= (x-2)(2x²+x-6)
=(x-2)(2x²+4x-3x-6)
=(x-2){2x(x+2)-3(x+2)}
=(x-2)(x+2)(2x-3)
Hence, Zeroes of the polynomial are 2 , -2 , 3/2
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