Math, asked by jitheeswar2406, 11 months ago

find all the zeros of 2 x power 4 - 3 x cube minus 3 X square + 6 x minus 2 if you know two zeros are root 2 and minus root 2 ​

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Answered by msdhewa2
2

Answer:

px =   {2x }^{4}   -  {3x}^{3}   -  {3x}^{2} + 6x - 2 \\ given \: zeros =  \sqrt{2} and -  \sqrt{2}  \\ x =  \sqrt{2 }  \:  \:  \: and \: x =   -  \sqrt{2}  \\ x -  \sqrt{2 }  = 0 \:  \:  \: and \:  \: x +  \sqrt{2 }  = 0 \\ multiplying \:  \\  |x -  \sqrt{2} |  \\  |x +  \sqrt{2} |  \\  {x}^{2}  - 2 \\ dividing \: px \: by \:  {x}^{2}  - 2  \\   \\ 2 {x}^{2}  - 3x + 1 = 0 \\  2 {x}^{2}  - 2x - x + 1  = 0\\ 2x(x - 1) - 1(x - 1) = 0 \\ (2x - 1)(x - 1) = 0 \\ x = 1.....x =  \frac{1}{2}  \\ hope \: this \:  helps \: you \: plzz \: mark \: as \: brinliest \: .......

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