Question

find all the zeros of 2x^4-2x^3-7x^2+3x+6 if two of its zeros are + or -√3/2​

Answer 1

Answer:

-1 and 2

Step-by-step explanation:

We will take the factor of the zeroes given to us.

√3/2 and -√3/2

they can be written as:

(x-√3/2) (x+√3/2)

solving further

x( x+√3/2) -√3/2( x +√3/2)

$x^{2}$ + √3/2x -√3/2x - 3/2

=> $x^{2}$-3/2 is the factor

By long division method, we divide 2x^4-2x^3-7x^2+3x+6 by $x^{2}$-3/2

we get the quotient : $2x^{2}$ - 2x - 4

By Splitting the middle term:

$2x^{2}$ - 2x - 4

$2x^{2}$ -4x + 2x -4

2x( x-2) +2( x-2)

(2x+2) ( x-2)

x= -1  x= 2 ans.

hope it helps