Question

Find all the zeros of (2x^4 - 3x^3– 5x^2 + 9x – 3), it being given that two of
its zeros are +root3 and - root3.
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Answer 1

Answer:

Step-by-step explanation:

The given polynomial is p(x)=2x⁴-3x³-5x²+9x-3

Two zeroes are-√3 and√3

So two factors of p(x) are (x-√3) and (x+√3)

So (x-√3)(x+√3)= x²-3 is a factor of p(x)

Hence p(x)÷(x²-3)=2x²-3x+1

Now 2x²-3x+1=2x²-2x-x+1

=2x(x-1)-1(x-1)

=(x-1)(2x-1)

Now x-1=0 or x=1

2x-1=0 or x=1/2

So the other two zeroes are 1 and1/2.