Question

Find all the zeros of 2x⁴-3x3³-3x²+6x-2 if you know that two zeros of it's zeroes are ½ and 1 ​

Answer 1

Answer:

As we can see that degree of the given polynomial is 4. And we have two zeroes already,hence we have to find another two zeroes. And those two zeroes are 2/√2 and -2√2

Step-by-step explanation:

We have two zeroes.

They are 1/2 and 1 .

Now x=1/2

x- 1/2 =0

Simmilarly x-1=0

multiplying both polynomials

x²-3x/2+1/2

by division method we have

(2x⁴-3x³-3x²+6x-2)÷(x²-3x/2+1/2)

= 2x²-4

splitting 2x²-4 we have

(√2x)²-(2)²

(√2x-2)(√2x+2)

x =2/√2 , -2√2