find all the zeros of f(x) = 2x3-7x2+3x+6 if its 2 zeros are root 3/2 and - root 3/2
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(x-√3/2)(x+√3/2)=x²-3/2
g(x)=x²-3/2
p(x)=2x^4-2x³-7x²+3x+6
then q(x)=2x²-2x-4
⇒2x²-2x-4=2x²+2x-4x-4=2x(x+1)-4(x+1)=(2x-4)(x+1)
⇒2x-4=0 or ⇒ x+1=0
⇒x=2 or ⇒ x= -1
g(x)=x²-3/2
p(x)=2x^4-2x³-7x²+3x+6
then q(x)=2x²-2x-4
⇒2x²-2x-4=2x²+2x-4x-4=2x(x+1)-4(x+1)=(2x-4)(x+1)
⇒2x-4=0 or ⇒ x+1=0
⇒x=2 or ⇒ x= -1
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