Question

find all the zeros of f x x cube + 13 x square + 32 + 20 if one of its zero is -2​

Answer 1

$(fx) \: \: {x}^{3} + 13 {x}^{2} + 32 + 20$

$0 = - 2$

${x}^{3} + 13 {x}^{2} + 50 = 0$

where as 0=-2
x^3 +13x^2+50=-2
x^3+169+50+2=0
x^3 +169+52=0
x^3=-169-52
x^3= -221