find all the zeros of p (x) = x cube +13x square + 32x+20. if one of its zero is -2
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Answer:
The zeros are -1, -2 and -10.
Step-by-step explanation:
Check first that -2 really is a zero of p(x)!
p(-2) = (-2)³ + 13(-2)² + 32(-2) + 20 = -8 + 52 - 64 + 20 = 0
Good!
Since -2 is a root of p(x), it follows that (x+2) is a factor. Dividing by (x+2):
p(x) = x³ + 13x² + 32x + 20 = ( x + 2 ) ( x² + 11x + 10 )
Factorizing the quadratic factor:
p(x) = ( x + 2 ) ( x² + 11x + 10 ) = ( x + 2 ) ( x + 1 ) ( x + 10 )
Therefore the other zeros are -1 and -10.
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