Question

Find all the zeros of the polynomial 2 x cube + x square - 6 x minus 3 if two of its zeros are minus root 3 and root 3

Answer 1

Answer:

-1/2

Step-by-step explanation:

First check that √3 and -√3 really are roots of 2x³ + x² - 6x - 3.

2(±√3)³ + (±√3)² - 6(±√3) -3 = ±6√3 + 3 - ±6√3 - 3 = 0.

Good!

Now the product of the roots of a polynomial is equal to the constant term divided by the leading coefficient, changing the sign if the degree is odd.

So here, the product is:  -(-3)/2 = 3/2.

Putting u for the third root, we then have

u × √3 × -√3 = 3/2

=> -3u = 3/2

=> u = -1/2

Answer 2

Answer: root3, -root3 and -1/2

Step-by-step explanation:

P(x)=2x³+x²-6x-3

Now here u go