Question

find all the zeros of the polynomial 2x^2-9​

Answer 1

Answer:

To find zeros, let

2x² - 9 = 0

∴(√2x)² - (3)² = 0

∴(√2x + 3)(√2x - 3) = 0

∴√2x+ 3 = 0        or            √2x - 3 = 0

∴x = -3/√2          or             x = 3/√2

Thus, zeros of the polynomial are -3/√2      and     3/√2

Answer 2

2x²-9= 0

2x²=9

x²=9/2

x= +-√9/2