find all the zeros of the polynomial 2x^4-10x^3+5x^2+15x-12 if it is given that two of its zeroes are root 3/2 and root -3/2
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Answered by
4
(x-3/2)(x+3/2)=x^2-9/4
divide p(x) by x^2-9/2
after that factorise the quotient By splitting the middle term
divide p(x) by x^2-9/2
after that factorise the quotient By splitting the middle term
Answered by
2
Answer:
x=9
Step-by-step explanation
cross multiply (10x^2+15x+63) with (x-5)________ I
cross multiply (5x^2-25x+12) with(2x+3)________II
=> 10x^3 -50x^2 +15x^2 -75x +63x -315 = 10x^3 +15x^2 -50x^2 - 75x +24x +36
=> cut [(10x^3) (-50x^2) (15x^2) (-75x)]
=> 63x-315=24x+36
=> 63x-24x=315+36
=> 39x=351
=> divied (39x=351) with (3)
=> 13x=117
=> x=9
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