find all the zeros of the polynomial 2x³ +x² -6x- 3,if two of its zeros are-√3 and√3
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2x³+x²-6x-3,
then two roots are
x=-√3,x=√3
(x+√3)(x-√3)=x²-y²
x²-(√3)²
x²-3 this will divide this eq. 2x³+x²-6x-3
x²-3)2x³+x²-6x-3(2x+1
2x. -6x
(-). (+)
_________
x²-3
x²-3
(-). (+)
_________
after it I think its two roots are 0,3
then two roots are
x=-√3,x=√3
(x+√3)(x-√3)=x²-y²
x²-(√3)²
x²-3 this will divide this eq. 2x³+x²-6x-3
x²-3)2x³+x²-6x-3(2x+1
2x. -6x
(-). (+)
_________
x²-3
x²-3
(-). (+)
_________
after it I think its two roots are 0,3
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