Question

find all the zeros of the polynomial p(x) = abx2 + (b + ac)x + bc
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Answer 1

Answer:

p(x) = abx2 + ( b + ac )x + bc

p'(x) = d/dx • [abx•2+(b+ac)x+bc]

p'(x) = d/dx • (abx + bx + acx + bc)

p'(x) = d/dx • (2abx) + d/dx • (bx) + d/dx (acx) + d/dx • (bc)

p'(x) = 2ab + b + ac + 0

p'(x) = 2ab + b + ac