find all the zeros of the polynomial x^4 - 7x^2 + 12 if two zeroes are root3 and - root3. please explain
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I hope this helps you
x^4-7x^2+12
x^2 -4
x^2 -3
(x^2-4)(x^2-3)=0
x^2-4=0
x= 2 x= -2
x^2-3=0
x= square root of 3
x= - square root of 3
x^4-7x^2+12
x^2 -4
x^2 -3
(x^2-4)(x^2-3)=0
x^2-4=0
x= 2 x= -2
x^2-3=0
x= square root of 3
x= - square root of 3
BrainofBrainly:
sorry this is not the answer....... there are a maximum of 4 zeroes i think 2 are given you need to find the rest
my question was that should we change it to standard form for doing it... but i got the answer thanx anyway
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