Question

find all the zeros of the polynomial x power 3 + 6 X square + 11 x + 6 if X + 1 is a factor​

Answer 1

$\huge{\boxed{\mathcal\pink{\fcolorbox{red}{purple}{SoLUTioN :-}}}}$

p(x) = x³+6x²+11x+6

hence,

g(x) = x+1 =0.

x = -1

so,

p(-1) = (-1)³ +6(-1)² +11(-1) +6

= -1 +6 -11 +6

= -12 +12 =0

➻❥T꙰H꙰A꙰N꙰K꙰Y꙰O꙰U꙰➻❥

♡ＬＯＶＥＹＯＵＲＳＥＬＦ♡

Answer 2

Answer:

p(x)=x³+6x²+11x+6

x+1 is a factor

x³+6x²+11x+6/x+1

=x²+5x+6

Splitting the middle term

x²+3x+2x+6

x(x+3)+2(x+3)

(x+2)(x+3)

Therefore, zeroes of the polynomial is

x+1=0

x=-1

x+2=0

x=-2

x+3=0

x=-3