find all the zeros of x4+x3 - 23x square - 3x+ 60 if it is given that two of its zeros are under root 3 and minus under root 3
please help me......
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Answers
Answered by
9
Hiiii friend,
(✓3) and (-✓3) are the two zeros of the given polynomial.
(X-✓3) (X+✓3) are also the factor of the given polynomial.
Therefore,
(X-✓3)(X+✓3) = (X)² - (✓3)² = X²-3
G(X) = X²-3
P(X) = X⁴+X³-23X²-3X+60
On dividing P(X) by G(X) we get,
Remainder = -54X+60
And,
Quotient = X²+X-17
Since Reminder is not 0 so ✓3 and -✓3 are not a factor of the given polynomial.
SOMETHING IS WRONG IN YOUR QUESTION.
HOPE IT WILL HELP YOU...... :-)
(✓3) and (-✓3) are the two zeros of the given polynomial.
(X-✓3) (X+✓3) are also the factor of the given polynomial.
Therefore,
(X-✓3)(X+✓3) = (X)² - (✓3)² = X²-3
G(X) = X²-3
P(X) = X⁴+X³-23X²-3X+60
On dividing P(X) by G(X) we get,
Remainder = -54X+60
And,
Quotient = X²+X-17
Since Reminder is not 0 so ✓3 and -✓3 are not a factor of the given polynomial.
SOMETHING IS WRONG IN YOUR QUESTION.
HOPE IT WILL HELP YOU...... :-)
Answered by
6
Answer
Step-by-step explanation:
The right answer is 4 and 5 .
Step by step explaination is given in the following image. Hope it helps.
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