find all the zeros of y cube minus 19 Y + 30 if it is given that one of its zeros is 2
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Answer:
here, 2 is one of the zero of p(y)
then , (y - 2) is a factor of p(y)
so we divide (y^3 -19y+30) by (y - 2) , we get :-
y^2 - 2y -15 as a quotient.
then , factories the quotient , we get :-
(y - 5) (y + 3) as a result....
then , y - 5 = 0
y = 5
& y + 3 = 0
y = - 3
hence , the remaining two zeros are : 5 & - 3 .
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Step-by-step explanation:
Then (y-2) is a fector of p(y)
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