find all the zeros when the one zeroes is (x2+(3- root 2)x-3 root 2) then find two others zero
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Step-by-step explanation:
p(x)=2x
3
+3x
2
−11x−6
Since x=−3 is a zero of p(x)
So, by factor theorem x+3 is a factor of p(x)
Now, if we divide 2x
3
+3x
2
−11x−6 by x+3, quotient is 2x
2
−3x−2 and remainder is 0.
Therefore,
2x
3
+3x
2
−11x=(x+3)(2x
2
−3x−2)
=(x+3)(2x+1)(x−2)
for other zeroes of p(x)
2x+1=0,x−2=0
Hence the other zeroes are −
2
1
,2
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