Math, asked by 44tfyuguugg, 1 month ago

find all the zeros when the one zeroes is (x2+(3- root 2)x-3 root 2) then find two others zero​

Answers

Answered by shraddha663
0

Step-by-step explanation:

p(x)=2x

3

+3x

2

−11x−6

Since x=−3 is a zero of p(x)

So, by factor theorem x+3 is a factor of p(x)

Now, if we divide 2x

3

+3x

2

−11x−6 by x+3, quotient is 2x

2

−3x−2 and remainder is 0.

Therefore,

2x

3

+3x

2

−11x=(x+3)(2x

2

−3x−2)

=(x+3)(2x+1)(x−2)

for other zeroes of p(x)

2x+1=0,x−2=0

Hence the other zeroes are −

2

1

,2

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