Question

Find all three-digit numbers that multiplied by 6 give a three-digit number with the same sum of digits as the original number

Answer 1

Answer:

First 3-digit number divisible by 6 = 102. Last 3-digit number divisible by 6 = 996. = > 102 + 108 + 114... +996

Step-by-step explanation:

Answer 2

Answer:

First 3-digit number divisible by 6 = 102. Last 3-digit number divisible by 6 = 996. = > 102 + 108 + 114... +996.