Question

find all values of k if the equation x^2 + (k-2)x + 10 - k =0 has equal roots.

Answer 1

Step-by-step explanation:

For equal roots

b^2-4ac=0

(k-2)^2-4×1×(10-k)=0

k^2+4-4k-40+4k=0

k^2-36=0

k^2=36

k=+6,-6. hope it will help you

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Answer 2

Answer:

Step-by-step explanation:

an equation has equal roots if

b^2=4*a*c

(k-2)^2=4*1*(10-k)

k^2+4-4k=40-4k

k^2=36

k=6,-6